document.write( "Question 1155969: At 10 a.m. a plane leaves Toronto for Vancouver a distance of 3000 kilometres. One hour later, a plane leaves Vancouver for Toronto. Both planes are travelling at a speed of 500 kilometres per hour. At what time (clock time) will the planes pass each other? \n" ); document.write( "
Algebra.Com's Answer #778661 by mananth(16946)![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "At 10 a.m. a plane leaves Toronto for Vancouver\r \n" ); document.write( "\n" ); document.write( "At 11 a.m. a plane leaves Vancouver for Toronto\r \n" ); document.write( "\n" ); document.write( "In 1 hour ( between 10 -11)the first plane has flown 500 km\r \n" ); document.write( "\n" ); document.write( "At 11.00 am the distance between them is 3000-500 - 2500 km\r \n" ); document.write( "\n" ); document.write( "They are moving towards each other. Catch up speed = (500 +500) 1000 km/h\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Time they meet 2500/1000\r \n" ); document.write( "\n" ); document.write( "they meet after 2.5 hours from 11.00 am\r \n" ); document.write( "\n" ); document.write( "You know when they met. \n" ); document.write( " |