document.write( "Question 107052This question is from textbook
\n" ); document.write( ": the minute hand of a clock is 3 cm longer then the hour hand. if the distance between the tips of the hands at nine o'clock is 15 cm, how long is the minute hand (hint: draw a diagram) \n" ); document.write( "
Algebra.Com's Answer #77865 by edjones(8007)\"\" \"About 
You can put this solution on YOUR website!
The hands form a right triangle with hypotenuse=15
\n" ); document.write( "Let x=length of hr hand, x+3=minute hand length
\n" ); document.write( "x^2+(x+3)^2=15^2
\n" ); document.write( "x^2+x^2+6x+9=225
\n" ); document.write( "2x^2+6x+9-225=0
\n" ); document.write( "2x^2+6x-216=0
\n" ); document.write( "2(x^2+3x-108)=0
\n" ); document.write( "2(x+12)(x-9)=0
\n" ); document.write( "x=-12 can't be an answer (negative)
\n" ); document.write( "x=9 cm
\n" ); document.write( "x+3=12 cm length of minute hand. Answer.
\n" ); document.write( "Check:
\n" ); document.write( "9^2+12^2=15^2
\n" ); document.write( "81+144=225 True
\n" ); document.write( "Ed\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );