document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=107037>Question 107037</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/1592009425/algebrahomeworkh>algebra 1 </A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> the sum of 3 digist is 5. The first and last digits are the same. If the middle digit is exchange with the first digit , then the number is 90 less than the original number. Find the original number. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #77862 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=77862\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x=\"first and last\", so 5-2x=middle\r<BR>\n" );
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document.write( "100(5-2x)+10x+x+90=100x+10(5-2x)+x ... 500-200x+11x+90=100x+50-20x+x ... 590-189x=81x+50\r<BR>\n" );
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document.write( "540=270x </SPAN>\n" );
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