document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1155927>Question 1155927</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Megan bought x pounds of coffee that costs 3 dollars per pound and 18 pounds of coffee at 2.5 per pound. Find the total number of coffee purchased if the average cost per pound of both types together is 2.85 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #778604 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=778604\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x*3=3x cost of 1 type. units are $<BR>\n" );
document.write( "18*2.50=45 of other type<BR>\n" );
document.write( "(18+x)*2.85=51.3+2.85x\r<BR>\n" );
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document.write( "3x+45+51.3+2.85x, the amount of the first two equals the total<BR>\n" );
document.write( "0.15x=6.3<BR>\n" );
document.write( "x=42 pounds <BR>\n" );
document.write( "that cost is $126<BR>\n" );
document.write( "18 pounds costs $45\r<BR>\n" );
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document.write( "60 pounds costs $171\r<BR>\n" );
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document.write( "171/60=$2.85\r<BR>\n" );
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document.write( "Answer is 60 pounds </SPAN>\n" );
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