document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=107032>Question 107032</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Stepdaughter called from Oregon with this problem....<BR>\n" );
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document.write( "                      3x + y =18<BR>\n" );
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document.write( "                      x +3y = 14         </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #77860 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=77860\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> multiplying first equation by -3 gives -9x-3y=-54 ... adding second equation gives -8x=-40, so x=5\r<BR>\n" );
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document.write( "5+3y=14 ... 3y=9 ... y=3 </SPAN>\n" );
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