document.write( "Question 1155862:  find the exact value between 0 to 2pi. 
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document.write( "tan (x/2)=cscx \n" );
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| Algebra.Com's Answer #778557 by Alan3354(69443)     You can put this solution on YOUR website! find the exact value between 0 to 2pi. \n" ); document.write( "tan (x/2)=cscx \n" ); document.write( "------------------ \n" ); document.write( "Sub u for x/2 \n" ); document.write( "--- \n" ); document.write( "tan(u) = 1/sin(2u) = 1/(2*sin(u)*cos(u)) \n" ); document.write( "sin(u)/cos(u) = 1/(2*sin(u)*cos(u)) \n" ); document.write( "sin(u) = 1/(2*sin(u)) \n" ); document.write( "2sin(u) = 1/sin(u) \n" ); document.write( "2sin^2(u) = 1 \n" ); document.write( "sin^2(u) = 1/2 \n" ); document.write( "==================\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |