document.write( "Question 1155862: find the exact value between 0 to 2pi.
\n" ); document.write( "tan (x/2)=cscx
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Algebra.Com's Answer #778557 by Alan3354(69443)\"\" \"About 
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find the exact value between 0 to 2pi.
\n" ); document.write( "tan (x/2)=cscx
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\n" ); document.write( "Sub u for x/2
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\n" ); document.write( "tan(u) = 1/sin(2u) = 1/(2*sin(u)*cos(u))
\n" ); document.write( "sin(u)/cos(u) = 1/(2*sin(u)*cos(u))
\n" ); document.write( "sin(u) = 1/(2*sin(u))
\n" ); document.write( "2sin(u) = 1/sin(u)
\n" ); document.write( "2sin^2(u) = 1
\n" ); document.write( "sin^2(u) = 1/2
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