document.write( "Question 1155690: Suppose the age at death for politicians can be modeled by an approximately normal distribution with a mean of 72.7 years and a standard deviation of 7.2 years.\r
\n" ); document.write( "\n" ); document.write( "Calculate the z-score representing the longest 20% of life expectancy for politicians. (Round your answer to two decimal places.)\r
\n" ); document.write( "\n" ); document.write( "Calculate the value (in years) representing the top 20% of life expectancies. (Round your answer to one decimal place.)
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Algebra.Com's Answer #778469 by Boreal(15235)\"\" \"About 
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The z-score =(x-mean)/sd
\n" ); document.write( "z(.20)=-0.842 so upper 20% is z=+0.84 (z (.80))
\n" ); document.write( "z=(x-mean)/sd
\n" ); document.write( ".84=(x-72.7)/7.2
\n" ); document.write( "6.05=x-72.7
\n" ); document.write( "x=78.75 or 78.8 years
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