document.write( "Question 1155801: A company sells a phone for 120$ each for 10 or less. For each phone in excess of 10, the price is decreased 4$ per phone for everyone. What number of phone will produce the greatest revenue for the company? \n" ); document.write( "
Algebra.Com's Answer #778463 by Boreal(15235)\"\" \"About 
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for x=1
\n" ); document.write( "that would be 116
\n" ); document.write( "for x=2 that would be 112
\n" ); document.write( "so revenue would be (10+x)(120-4x)
\n" ); document.write( "that is 1200+80x-4x^2 and has to be maximized
\n" ); document.write( "with x=-b/2a for the vertex, x is -80/-8=10
\n" ); document.write( "20 phones is the greatest revenue with 20*(120-40)=$1600
\n" ); document.write( "19 wold be 19*84=$1596
\n" ); document.write( "and 21 would be 21*76, also $1596
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