document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1155804>Question 1155804</A>: <I><SPAN STYLE=\"word-break: break-all;\"> write the polynomial function of minimum degree in standard form that has zero -1 and 2i. Assume the leading coefficient is 1. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #778461 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=778461\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> -2i and +2i are roots, since complex roots are conjugate<BR>\n" );
document.write( "-1 is other,<BR>\n" );
document.write( "(x+1)<BR>\n" );
document.write( "x=2i, x= -2i. (x^2+4)=0<BR>\n" );
document.write( "(x+1)(x^2+4)<BR>\n" );
document.write( "x^3+x^2+4x+4=0\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "also,<BR>\n" );
document.write( "if first coefficient is 1 then <BR>\n" );
document.write( "x=(1/2)(-b+/- sqrt(b^2-4ac)<BR>\n" );
document.write( "the discriminate is -16 and b is 0<BR>\n" );
document.write( "therefore -4ac=-16<BR>\n" );
document.write( "a is 1, c=4<BR>\n" );
document.write( "(x^2+4)\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );