document.write( "Question 1155804: write the polynomial function of minimum degree in standard form that has zero -1 and 2i. Assume the leading coefficient is 1. \n" ); document.write( "

Algebra.Com's Answer #778460 by MathLover1(20850) $\"\"$ $\"About$

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\n" ); document.write( "\n" ); document.write( "function of minimum degree in standard form that has zeros\r
\n" ); document.write( "\n" ); document.write( " $\"x%5B1%5D=-1\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"+x%5B2%5D=2i\"$ -> since complex zeros come in pairs, you also have\r
\n" ); document.write( "\n" ); document.write( " $\"+x%5B3%5D=-2i\"$ \r
\n" ); document.write( "\n" ); document.write( "then\r
\n" ); document.write( "\n" ); document.write( " $\"f%28x%29=%28x-x%5B1%5D%29%28x-x%5B2%5D%29%28x-x%5B3%5D%29\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"f%28x%29=%28x-%28-1%29%29%28x-2i%29%28x-%28-2i%29%29\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"f%28x%29=%28x%2B1%29%28x-2i%29%28x%2B2i%29\"$ .....use the rule for difference of squares \r
\n" ); document.write( "\n" ); document.write( " $\"f%28x%29=%28x%2B1%29%28x%5E2-%282i%29%5E2%29\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"f%28x%29=%28x%2B1%29%28x%5E2-4%28i%29%5E2%29\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"f%28x%29=%28x%2B1%29%28x%5E2-4%28-1%29%29\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"f%28x%29=%28x%2B1%29%28x%5E2%2B4%29\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"f%28x%29=x%5E3%2B4x%2Bx%5E2%2B4\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"f%28x%29=x%5E3%2Bx%5E2%2B4x%2B4\"$ \r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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