document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=106966>Question 106966</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Convert each quadratic function into vertex form.  State the vertex, axis of symmetry, and direction of opening:<BR>\n" );
document.write( "1.  y = 2x^2-4x+3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #77846 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=77846\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> general equation is y=a(x-h)^2+k\r<BR>\n" );
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document.write( "y=2(x^2-2x)+3 ... adding 1 inside the parentheses makes (x-1)^2<BR>\n" );
document.write( "...but you can't just add to one side of an equation<BR>\n" );
document.write( "...and adding 1 inside the parentheses is effectively adding 2, so 2 is also subtracted\r<BR>\n" );
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document.write( "y=2(x^2-2x+1)+3-2 ... y=2(x-1)^2+1\r<BR>\n" );
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document.write( "so the vertex is (1,1)\r<BR>\n" );
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document.write( "axis of symmetry goes through the vertex\r<BR>\n" );
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document.write( "the sign of a tells direction of opening </SPAN>\n" );
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