document.write( "Question 1155803: The sum of 39 consecutive number is 1170, what is the largest of these 39 number could be? \n" ); document.write( "

Algebra.Com's Answer #778456 by greenestamps(13203) $\"\"$ $\"About$

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\n" ); document.write( "The sum of 39 consecutive $\"cross%28number%29\"$ integers is 1170, what is the largest of these 39 $\"cross%28number+could+be%29\"$ integers?

\n" ); document.write( "(If the sum of 39 consecutive integers is 1170, then there is only one integer that the largest one can be.)

\n" ); document.write( "The sum of the 39 integers is 1170; the average is 1170/39 = 30.

\n" ); document.write( "In a set of consecutive integers, the one in the middle is the average.

\n" ); document.write( "In a set of 39 consecutive integers, there is a middle number, with 19 larger integers and 19 smaller. So the smallest of the 39 integers is 30-19 = 11 and the largest is 30+19 = 49.

\n" ); document.write( "ANSWER: 49

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