document.write( "Question 1155760: A genetic experiment with peas resulted in one sample of offspring that consisted of 439 green peas and 157 yellow peas.
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\n" ); document.write( "a. Construct a 95​% confidence interval to estimate of the percentage of yellow peas.\r
\n" ); document.write( "\n" ); document.write( "b. It was expected that​ 25% of the offspring peas would be yellow. Given that the percentage of offspring yellow peas is not​ 25%, do the results contradict​ expectations?
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Algebra.Com's Answer #778404 by Boreal(15235)\"\" \"About 
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half-interval is sample mean +/- 1.96*sqrt(p*(1-p)/n)
\n" ); document.write( "x bar is (157/596)=0.263
\n" ); document.write( "sqrt(.263*.737)=sqrt (0.000325)=0.0180
\n" ); document.write( "half-interval is 0.035
\n" ); document.write( "95%CI is (0.228, 0.298)
\n" ); document.write( "Since 0.25 is in the interval the results do not contradict expectations.
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