document.write( "Question 1155760: A genetic experiment with peas resulted in one sample of offspring that consisted of 439 green peas and 157 yellow peas.
\n" );
document.write( "
\n" );
document.write( "a. Construct a 95% confidence interval to estimate of the percentage of yellow peas.\r
\n" );
document.write( "\n" );
document.write( "b. It was expected that 25% of the offspring peas would be yellow. Given that the percentage of offspring yellow peas is not 25%, do the results contradict expectations? \n" );
document.write( "
Algebra.Com's Answer #778404 by Boreal(15235) You can put this solution on YOUR website! half-interval is sample mean +/- 1.96*sqrt(p*(1-p)/n) \n" ); document.write( "x bar is (157/596)=0.263 \n" ); document.write( "sqrt(.263*.737)=sqrt (0.000325)=0.0180 \n" ); document.write( "half-interval is 0.035 \n" ); document.write( "95%CI is (0.228, 0.298) \n" ); document.write( "Since 0.25 is in the interval the results do not contradict expectations. \n" ); document.write( " \n" ); document.write( " |