document.write( "Question 1155751: Given a family with four children, find the probability of the event.
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document.write( "The oldest is a girl and the youngest is a boy, given that there is at least one boy and at least one girl. \n" );
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Algebra.Com's Answer #778398 by greenestamps(13209) You can put this solution on YOUR website! \n" ); document.write( "First consider the probability that with four children the first is a girl and the last is a boy: \n" ); document.write( "P(GxxB) = (1/2)(2/2)(2/2)(1/2) = 4/16 \n" ); document.write( "Now consider the requirement that there be at least one boy and at least one girl. That eliminates two possible cases -- all boys or all girls -- so the denominator of the probability fraction is 16-2 = 14. \n" ); document.write( "Of the two cases that were thrown out, neither has a girl first and a boy last, so the numerator of the probability fraction is still 4. \n" ); document.write( "ANSWER: 4/14, or 2/7 \n" ); document.write( "Note there are other formal ways of calculating that probability; however, for a small problem like this, it is easiest simply to list all 16 possible sequences of 4 boys or girls and find how many satisfy the given conditions. 14 of the 16 satisfy the condition that there is at least one boy and one girl; and 4 of those 14 have a girl first and a boy last. \n" ); document.write( " \n" ); document.write( " |