document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1155701>Question 1155701</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A pool can be filled in 96 hours and drained in 144 hours. How many hours will it take to fill the pool if both the fill and drain pipes are on </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #778342 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13216)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=778342\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "Here is an alternative to the method shown by tutor @ikleyn for solving problems like this.  For this particular problem, it makes the solution almost trivial.<br><BR>\n" );
document.write( "Consider the least common multiple of the two given times -- 96 hours and 144 hours.  The least common multiple of those two times is 288 hours.<br><BR>\n" );
document.write( "In 288 hours, the pool could be filled 288/96 = 3 times and it could be drained 288/144 = 2 times.<br><BR>\n" );
document.write( "So in 288 hours with both the fill and drain pipes open the pool could be filled 3-2=1 time.<br><BR>\n" );
document.write( "ANSWER: It takes 288 hours for the pool to fill if both pipes are open.<br><BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );