document.write( "Question 1155706: Twice last​ month, Judy Carter rented a car from a car rental company and traveled around the Southwest on business. The company rents its car for a daily​ fee, plus an additional charge per mile driven. Judy recalls that her first trip lasted 4​ days, she drove 450​ miles, and the rental cost her $ 210.00 . On her second business trip she drove 200 miles in 3​ days, and paid $ 130.00 for the rental. Find the daily​ fee, and find the mileage charge.
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Algebra.Com's Answer #778341 by ankor@dixie-net.com(22740)\"\" \"About 
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Twice last​ month, Judy Carter rented a car from a car rental company and traveled around the Southwest on business.
\n" ); document.write( " The company rents its car for a daily​ fee, plus an additional charge per mile driven.
\n" ); document.write( " Judy recalls that her first trip lasted 4​ days, she drove 450​ miles, and the rental cost her $ 210.00 .
\n" ); document.write( " On her second business trip she drove 200 miles in 3​ days, and paid $ 130.00 for the rental.
\n" ); document.write( " Find the daily​ fee, and find the mileage charge.
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\n" ); document.write( "let f = the daily fee
\n" ); document.write( "let m = cost per mile
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\n" ); document.write( "Write a equation for each trip
\n" ); document.write( "\"first trip lasted 4​ days,she drove 450​ miles, and the rental cost her $210.00\"
\n" ); document.write( "4f + 450m = 210
\n" ); document.write( "\"second business trip she drove 200 miles in 3​ days, and paid $ 130.00\"
\n" ); document.write( "3f + 200m = 130
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\n" ); document.write( "use elimination, mult the 1st eq by 3, the 2nd eq by 4
\n" ); document.write( "12f + 1350m = 630
\n" ); document.write( "12f + 800m = 520
\n" ); document.write( "---------------------subtraction eliminates f, find m
\n" ); document.write( "0 + 550m = 110
\n" ); document.write( "m = 110/550
\n" ); document.write( "m = $.20 cents per mile
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\n" ); document.write( "Find f using the 2nd original equation
\n" ); document.write( "3f + 200(.20) = 130
\n" ); document.write( "3f + 40 = 130
\n" ); document.write( "3f = 130 - 40
\n" ); document.write( "f = 90/3
\n" ); document.write( "f = $30 is the daily fee
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\n" ); document.write( "Check these solutions in the 1st equation
\n" ); document.write( "4(30) + 450(.20) =
\n" ); document.write( "120 + 90 = 210\r
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