document.write( "Question 1155702: Sue can do an inventory by herself in 6 hours. Sue and Ann work together on the inventory for 3 hours. Then Ann finishes up the job by herself in 2 additional hours. How many hours would it take Ann to do the entire inventory if she worked alone? \n" ); document.write( "
Algebra.Com's Answer #778337 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! Sue can do an inventory by herself in 6 hours. \n" ); document.write( " Sue and Ann work together on the inventory for 3 hours. \n" ); document.write( " Then Ann finishes up the job by herself in 2 additional hours. \n" ); document.write( " How many hours would it take Ann to do the entire inventory if she worked alone? \n" ); document.write( ": \n" ); document.write( "let a = time required by Ann working alone \n" ); document.write( "let the completed job = 1 \n" ); document.write( "\"Sue and Ann work together on the inventory for 3 hours. Then Ann finishes up the job by herself in 2 additional hours.\" \n" ); document.write( "Sue works a total of 5 hrs, Ann works 3 \n" ); document.write( " \n" ); document.write( "Multiply equation by 6a \n" ); document.write( "5a + 6(3) = 6a \n" ); document.write( "18 = 6a - 5a \n" ); document.write( "18 = a \n" ); document.write( "Ann required 18 hrs to do the job alone \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "See if that checks out \n" ); document.write( " \n" ); document.write( " |