document.write( "Question 1155541: How many randomly selected employers (minimum number) must we contact in order to guarantee a margin of error of no more than 4% (at 95% confidence)?\r
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document.write( "A.600
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document.write( "B.400
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document.write( "C.550
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document.write( "D.1000
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Algebra.Com's Answer #778318 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! margins of error estimate is 1/sqrt(n) \n" ); document.write( "if 0.04=1/25 is margin of error \n" ); document.write( "then n=25^2 or 625. \n" ); document.write( "Choose 600.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |