document.write( "Question 1155679: The amount of Jenns phone bill is normally distributed with a mean of $65 and a standard deviation of $9. What percentage of her phone bills are between 32$ and 92? \n" ); document.write( "
Algebra.Com's Answer #778315 by Boreal(15235)\"\" \"About 
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z=(x-mean)/sd
\n" ); document.write( "low end z=(32-65)/9=-33/9
\n" ); document.write( "high end z=(92-65)/9=3
\n" ); document.write( "The probability of z between -3.67 and 3 is 0.9985
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