document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1155675>Question 1155675</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you help me with this equation. I am really confused. ok so the question is \r<BR>\n" );
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document.write( "\"An angle measures 144° more than the measure of its supplementary angle. What is the measure of each angle?\" \r<BR>\n" );
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document.write( "Can you help me figure out how to solve this for future questions like this in my assignments? Please.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #778290 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=778290\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> two angles are supplementary if they add to 180 degrees<BR>\n" );
document.write( "let one be x<BR>\n" );
document.write( "The other has to be 180-x<BR>\n" );
document.write( "but x is also 144 more than 180-x, just inserting the 144 into the x and 180-x statement<BR>\n" );
document.write( "x-144=180-x<BR>\n" );
document.write( "2x=36<BR>\n" );
document.write( "x=18 degrees<BR>\n" );
document.write( "180-x=162 degrees.  Those are the angles, and 162-144=18. </SPAN>\n" );
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