document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1155586>Question 1155586</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The cost of making x skirts per day is given by the equation C = 2x^2 -160x + 3600, where c is the cost in dollars. How many skirts should be produced in order to minimize costs? What is the minimum cost? I do not know how to solve for the answer.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #778174 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=778174\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The cost of making x skirts per day is given by the equation C = 2x^2 -160x + 3600, where c is the cost in dollars. How many skirts should be produced in order to minimize costs? What is the minimum cost?<BR>\n" );
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document.write( "Find the vertex of the parabola C = 2x^2 -160x + 3600<BR>\n" );
document.write( "It's at x = -b/2a = 160/4 = 40<BR>\n" );
document.write( "40 skirts ---> minumum Cost<BR>\n" );
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document.write( "What is the minimum cost?<BR>\n" );
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document.write( "C(x) = 2x^2 -160x + 3600<BR>\n" );
document.write( "C(40) = 2*1600 - 160*40 + 3600<BR>\n" );
document.write( "= 3200 - 6400 + 3600<BR>\n" );
document.write( "= $400<BR>\n" );
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