document.write( "Question 1155559: Solving:\r
\n" ); document.write( "\n" ); document.write( " 5 x-3y = 18
\n" ); document.write( " -3 x-3y = -12 \r
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\n" ); document.write( "\n" ); document.write( "Using Substitution Method.\r
\n" ); document.write( "\n" ); document.write( "Expressing x as a function of y (from the first equation) x = (18 +3y)/5\r
\n" ); document.write( "\n" ); document.write( "Substituting this expression into the second equation:\r
\n" ); document.write( "\n" ); document.write( " -3 (18 -3y)/5-3y = -12 \r
\n" ); document.write( "\n" ); document.write( "Why is this not -3(18+3y)/5-3y = -12 ?
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Algebra.Com's Answer #778171 by ikleyn(52787)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "            I will do it using substitution method,  but I will use a  TRICK  to avoid using fractions on the way.\r
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document.write( "Express 3y from the first equation  3y = 5x - 18  and then substitute this expression into the second equation, replacing 3y there\r\n" );
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document.write( "    -3x - (5x-18) = -12.\r\n" );
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document.write( "Now simplify and find x\r\n" );
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document.write( "    - 3x - 5x + 18 = -12\r\n" );
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document.write( "    - 8x           = - 12 - 18\r\n" );
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document.write( "     -8x           = - 30\r\n" );
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document.write( "       x = \"%28-30%29%2F%28-8%29\" = \"30%2F8\" = 3.75.\r\n" );
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document.write( "Now you substitute this found value of x into either of the two original equations and find y.\r\n" );
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\n" ); document.write( "\n" ); document.write( "Learn this trick from my post.\r
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\n" ); document.write( "\n" ); document.write( "There is a lesson in this site, demonstrating this trick in work\r
\n" ); document.write( "\n" ); document.write( "    - Useful tricks when solving systems of 2 equations in 2 unknowns by the Substitution method \r
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