document.write( "Question 1155559: Solving:\r
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document.write( " 5 x-3y = 18
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document.write( " -3 x-3y = -12 \r
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document.write( "Using Substitution Method.\r
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document.write( "Expressing x as a function of y (from the first equation) x = (18 +3y)/5\r
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document.write( "Substituting this expression into the second equation:\r
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document.write( " -3 (18 -3y)/5-3y = -12 \r
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document.write( "Why is this not -3(18+3y)/5-3y = -12 ?
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Algebra.Com's Answer #778171 by ikleyn(52787)![]() ![]() You can put this solution on YOUR website! .\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " I will do it using substitution method, but I will use a TRICK to avoid using fractions on the way.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " Watch my steps carefully.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "Express 3y from the first equation 3y = 5x - 18 and then substitute this expression into the second equation, replacing 3y there\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " -3x - (5x-18) = -12.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Now simplify and find x\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " - 3x - 5x + 18 = -12\r\n" ); document.write( "\r\n" ); document.write( " - 8x = - 12 - 18\r\n" ); document.write( "\r\n" ); document.write( " -8x = - 30\r\n" ); document.write( "\r\n" ); document.write( " x =\r \n" ); document.write( "\n" ); document.write( "--------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Learn this trick from my post.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "There is a lesson in this site, demonstrating this trick in work\r \n" ); document.write( "\n" ); document.write( " - Useful tricks when solving systems of 2 equations in 2 unknowns by the Substitution method \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |