document.write( "Question 1155466: The following table describes the result of road-worthiness tests of Ford Focus cars that are three years old (based on data from the department of transportation ). The random variable x represents the number of cars that failed among five that were tested for road-worthiness
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document.write( " x
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document.write( " P(x)
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document.write( " 0
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document.write( " 0.377
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document.write( " 1
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document.write( " 0.399
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document.write( " 2
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document.write( " 0.176
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document.write( " 3
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document.write( " 0.041
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document.write( " 4
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document.write( " 0.005
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document.write( " 5
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document.write( "0
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document.write( "Find the probability of getting three or more cars that fail among five cars tested,
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document.write( "Group of answer choices\r
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document.write( "0.046\r
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document.write( "0.005\r
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document.write( "\n" );
document.write( "0.222\r
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document.write( "\n" );
document.write( "0.048 \n" );
document.write( "
Algebra.Com's Answer #778080 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! Three or more is the sum of p(3),p(4), and p(5)=0.041+0.005+0=0.046 \n" ); document.write( " |