document.write( "Question 1155466: The following table describes the result of road-worthiness tests of Ford Focus cars that are three years old (based on data from the department of transportation ). The random variable x represents the number of cars that failed among five that were tested for road-worthiness 
\n" ); document.write( "   x
\n" ); document.write( "  P(x)
\n" ); document.write( "   0
\n" ); document.write( " 0.377
\n" ); document.write( "   1
\n" ); document.write( " 0.399
\n" ); document.write( "   2
\n" ); document.write( " 0.176
\n" ); document.write( "   3
\n" ); document.write( " 0.041
\n" ); document.write( "   4
\n" ); document.write( " 0.005
\n" ); document.write( "   5
\n" ); document.write( "0
\n" ); document.write( "Find the probability of getting three or more cars that fail among five cars tested,
\n" ); document.write( "Group of answer choices\r
\n" ); document.write( "\n" ); document.write( "0.046\r
\n" ); document.write( "\n" ); document.write( "0.005\r
\n" ); document.write( "\n" ); document.write( "0.222\r
\n" ); document.write( "\n" ); document.write( "0.048
\n" ); document.write( "

Algebra.Com's Answer #778080 by Boreal(15235)\"\" \"About 
You can put this solution on YOUR website!
Three or more is the sum of p(3),p(4), and p(5)=0.041+0.005+0=0.046 \n" ); document.write( "
\n" );