document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=106959>Question 106959</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the three consecutive numbers such that the sum of double the first and the third totals 362 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #77807 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=77807\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x, x+1, x+2 are the three consecutive numbers.<BR>\n" );
document.write( "2x+(x+2)=362<BR>\n" );
document.write( "2x+x+2=362<BR>\n" );
document.write( "3x=362-2<BR>\n" );
document.write( "3x=360<BR>\n" );
document.write( "x=360/3<BR>\n" );
document.write( "x=120 answer for the first number.<BR>\n" );
document.write( "x+2=122 answer for the third number.<BR>\n" );
document.write( "proof:<BR>\n" );
document.write( "2*120+122=362<BR>\n" );
document.write( "240+122=362<BR>\n" );
document.write( "362=362<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );