document.write( "Question 1155461: Hello, can someone please help me with this problem:
\n" ); document.write( "Rewrite y=5(1/4)^{t/6} in the form y=a(1+r)^t or y=a(1-r)^t. Round the value of r to the nearest ten-thousandth. Then tell whether the model represents exponential growth or exponential decay.\r
\n" ); document.write( "\n" ); document.write( "I know that it represents exponential decay but I don't understand how to rewrite in that form.\r
\n" ); document.write( "\n" ); document.write( "Someone, please help. Thanks \n" ); document.write( "

Algebra.Com's Answer #778060 by ikleyn(52781) $\"\"$ $\"About$

You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( " Hello, it is very simple to do.\r
\n" ); document.write( "\n" ); document.write( " I will show it to you now.\r
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document.write( "y = 5*(1/4)^(t/6).           (1)\r\n" );
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document.write( "According to the properties of exponents\r\n" );
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document.write( "    y = 5*((1/4)^(1/6))^t.   (2)    \r\n" );
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document.write( "Calculate  (1/4)^(1/6).  It is (use your calculator)\r\n" );
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document.write( "    (1/4)^(1/6) = 0.793701 = 1 -r.\r\n" );
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document.write( "Hence,  r = 1 - 0.793701 = 0.206299,  \r\n" );
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document.write( "or, rounding the value of \"r\" to the nearest ten-thousandth,\r\n" );
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document.write( "    r = 0.20630.\r\n" );
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document.write( "Therefore, your answer is   y = 5*(1-0.20630)^t.\r\n" );
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document.write( "It is  EXACTLY  the form you requested, with the value of r = 0.20630, rounded as it is assigned by the problem.\r\n" );
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\n" ); document.write( "\n" ); document.write( "I answered your question.   My answer is EXACTLY what the problem asks about.\r
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\n" ); document.write( "\n" ); document.write( "        What @MathLover wrote in her post, is \r
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\n" ); document.write( "\n" ); document.write( "           1)   IRRELEVANT,\r
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\n" ); document.write( "\n" ); document.write( "      and\r
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\n" ); document.write( "\n" ); document.write( "           2)   GIBBERISH.\r
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\n" ); document.write( "\n" ); document.write( "For your safety, simply ignore her post.\r
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\n" ); document.write( "\n" ); document.write( "She wrote similar   GIBBERISH   yesterday two or more times, answering other your posts.\r
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\n" ); document.write( "\n" ); document.write( "You may ignore her writing too,   by the same reasons.\r
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\n" ); document.write( "\n" ); document.write( "Dear @MathLover1,\r
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\n" ); document.write( "\n" ); document.write( "now I really think that the time just came for you to stop your exercises at this forum.\r
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