document.write( "Question 1155447: You need 270 mL of a 55% alcohol solution. On hand, you have a 50% alcohol mixture and a 80% alcohol mixture. How much of each mixture will you need to obtain the desired solution? \n" ); document.write( "

Algebra.Com's Answer #778027 by josgarithmetic(39616) $\"\"$ $\"About$

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Just looking at the concentration values, see one part out of six parts from 50% to 80%; the wanted 55% is one part. You want most of the alcohol solution to come from the 50% and the rest from the 80%. Think 270*(5/6)=225 mL from the 50% and 45 mL from the 80%.\r
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\n" ); document.write( "\n" ); document.write( "v, amount of the 80%
\n" ); document.write( "270-v, amount of the 50%
\n" ); document.write( "55, the target concentration percent wanted\r
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\n" ); document.write( "\n" ); document.write( " $\"80v%2B50%28270-v%29=55%2A270\"$ \r
\n" ); document.write( "\n" ); document.write( "after doing the algebra steps,\r
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\n" ); document.write( "\n" ); document.write( " $\"highlight%28v=270%28%2855-50%29%2F%2880-50%29%29%29\"$ -------volume of the 80% alcohol to use. \n" ); document.write( "

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