document.write( "Question 106920: Jill had $3.50 in nickel and dimes. If she has 50 coins, how many of each type of coins does she have? \n" ); document.write( "
Algebra.Com's Answer #77798 by checkley75(3666)![]() ![]() ![]() You can put this solution on YOUR website! N+D=50 OR N=50-D \n" ); document.write( ".05(50-D)+.10D=3.50 \n" ); document.write( "2.5-.05D+.10D=3.50 \n" ); document.write( ".05D=3.50-2.50 \n" ); document.write( ".05D=1.00 \n" ); document.write( "D=1.00/.05 \n" ); document.write( "D=20 NUMBER OF DIMES. \n" ); document.write( "50-20=30 NUMBER OF NICKLES. \n" ); document.write( "PROOF \n" ); document.write( ".05*30+.10*20=3.50 \n" ); document.write( "1.50+2.00=3.50 \n" ); document.write( "3.50=3.50 \n" ); document.write( " |