document.write( "Question 1155356: Assume that adults have IQ scores that are normally distributed with a mean of 102.6 and a standard deviation of 21.2. Find the probability that a randomly selected adult has an IQ greater than 133.7. ​ \n" ); document.write( "
Algebra.Com's Answer #777953 by VFBundy(438)\"\" \"About 
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z-score = \"%28x+-+mean%29%2FSD\" = \"%28133.7-102.6%29%2F21.2\" = \"31.1%2F21.2\" = 1.47
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\n" ); document.write( "Look up 1.47 on a z-table. The result is 0.9292. This is the probability that someone's IQ is LESS than 133.7. That means the probability that someone's IQ is GREATER than 133.7 is 0.0708.
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