document.write( "Question 1155366: Please help me to answer this:\r
\n" ); document.write( "\n" ); document.write( "For 0° ≤ x ≤ 360°, find the number of roots the equation 2sinxtanx = -tanx
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Algebra.Com's Answer #777944 by math_helper(2461)\"\" \"About 
You can put this solution on YOUR website!
The first thing is to look for zeros:
\n" ); document.write( "tan(x)=0 at 0, 180, and 360 degrees, and these are all solutions.
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\n" ); document.write( "For non-zero solutions:\r
\n" ); document.write( "\n" ); document.write( "Simplify \"2sin%28x%29tan%28x%29+=+-tan%28x%29+\" to \"+sin%28x%29+=+-1%2F2+\", \"tan%28x%29%3C%3E0\"
\n" ); document.write( "and recall:
\n" ); document.write( "\"sin%2830%5Eo%29+=+1%2F2+\" and
\n" ); document.write( "in Q1,Q2,Q3,Q4, sin(x) is +,+,-,-, respectively.
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\n" ); document.write( "\n" ); document.write( "Working from the x-axis, push the angle into Q3 by adding 180+30 = 210 and into Q4 by subtracting 30 from 360, giving \"cross%28310%29\"330 (edited typo here).
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\n" ); document.write( "A picture is worth a thousand words:
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\n" ); document.write( "And note if you rearrange to 2sin(x)tan(x)+tan(x) = 0 and graph the LHS, you can simply look for where this rearranged function crosses the x-axis:\r
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