document.write( "Question 1155366:  Please help me to answer this:\r
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document.write( "For 0° ≤  x  ≤  360°, find the number of roots the equation 2sinxtanx = -tanx \n" );
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| Algebra.Com's Answer #777944 by math_helper(2461)     You can put this solution on YOUR website! The first thing is to look for zeros: \n" ); document.write( "tan(x)=0 at 0, 180, and 360 degrees, and these are all solutions. \n" ); document.write( " \n" ); document.write( "For non-zero solutions:\r \n" ); document.write( "\n" ); document.write( "Simplify \n" ); document.write( "and recall: \n" ); document.write( " \n" ); document.write( "in Q1,Q2,Q3,Q4, sin(x) is +,+,-,-, respectively. \r \n" ); document.write( "\n" ); document.write( "Working from the x-axis, push the angle into Q3 by adding 180+30 = 210 and into Q4 by subtracting 30 from 360, giving \r \n" ); document.write( "\n" ); document.write( "Solutions are \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "A picture is worth a thousand words: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "And note if you rearrange to 2sin(x)tan(x)+tan(x) = 0 and graph the LHS, you can simply look for where this rearranged function crosses the x-axis:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |