document.write( "Question 1155352: Let a be directly proportional to m and n^2, and inversely proportional to y^3. If a=4 when m=9, n=4, and y=2, find a when m=8, n=3, and y=5. \n" ); document.write( "

Algebra.Com's Answer #777925 by MathLover1(20850) $\"\"$ $\"About$

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$\"a=+km%2An%5E2%E2%80%8B\"$ and
\n" ); document.write( " $\"a=k%2Fy%5E3\"$ \r
\n" ); document.write( "\n" ); document.write( "=> $\"a=+k%28m%2An%5E2%2Fy%5E3%29\"$ \r
\n" ); document.write( "\n" ); document.write( " If $\"a=4\"$ when $\"m=9%E2%80%8B\"$ , $\"n=4%E2%80%8B\"$ , and $\"y=2\"$ , we have \r
\n" ); document.write( "\n" ); document.write( " $\"a=+k%289%2A4%5E2%2F2%5E3%29\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"4=144k%2F8\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"32=144k\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"k=32%2F144\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"k=2%2F9\"$ \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "=> $\"a=+%282%2F9%29%28m%2An%5E2%2Fy%5E3%29\"$ \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "find $\"a\"$ when $\"m=8%E2%80%8B\"$ , $\"n=3%E2%80%8B\"$ , and $\"y=5\"$ \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " $\"+a=+%282%2F9%29%288%2A3%5E2%2F5%5E3%29\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"+a=+16%2F125\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"a=0.128\"$ \r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

\n" );