document.write( "Question 1155346: A coffee distributor needs to mix a(n) Mexican Shade Grown coffee blend that normally sells for $10.10 per pound with a Arabian Mocha coffee blend that normally sells for $14.30 per pound to create 20 pounds of a coffee that can sell for $13.46 per pound. How many pounds of each kind of coffee should they mix? \n" ); document.write( "
Algebra.Com's Answer #777922 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "Using a traditional algebraic approach....

\n" ); document.write( "x pounds at $10.10 per pound, plus (20-x) pounds at $14.30 per pound equals 20 pounds at $13.46 per pound:

\n" ); document.write( "\"10.10%28x%29%2B14.30%2820-x%29+=+13.46%2820%29\"
\n" ); document.write( "\"10.10x%2B286-14.30x+=+269.2\"
\n" ); document.write( "...

\n" ); document.write( "You can finish the problem by that method....

\n" ); document.write( "Here is a method for solving this problem by a very different method which requires less time and effort.

\n" ); document.write( "Key idea: the ratio in which the two ingredients must be mixed is exactly determined by where the price of the mixture lies between the prices of the two ingredients.

\n" ); document.write( "(1) 14.30-10.10 = 4.20
\n" ); document.write( "(2) 13.46-10.10 = 3.36
\n" ); document.write( "(3) The mixture price of $13.46 per pound is 336/420 = 84/105 = 4/5 of the way from the $10.10 price of the first ingredient and the $14.30 price of the second.
\n" ); document.write( "(4) That means 4/5 of the mixture needs to be the second ingredient.

\n" ); document.write( "ANSWER: 4/5 of 20 pounds, or 16 pounds, of the Arabian Mocha blend; the remaining 4 pounds of the Mexican blend.

\n" ); document.write( "CHECK:
\n" ); document.write( "16(14.30)+4(10.10) = 269.2
\n" ); document.write( "20(13.46) = 269.2

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