document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1155286>Question 1155286</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Assume that a normal distribution of data has a mean of 24 and a standard deviation of 4. Use the 68, 95, 99.7 rule to find the percentage of values that lie below 16. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #777903 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=777903\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 68 means 1 sd on each side included.  So that would be 24-4 and 24+4 or interval (20, 28) <BR>\n" );
document.write( "For 95 it is 2 sd s and that would be (16, 32) The percentage below 16 if 2.5%, since the remaining 5% is split above 32 and below 16. ANSWER<BR>\n" );
document.write( "For 99.7 it is 3 sd s and that would be (12, 36) </SPAN>\n" );
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