document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=15762>Question 15762</A>: <I><SPAN STYLE=\"word-break: break-all;\"> please help me on this one..  if 2t + 3 = -9 what is the value of -3t - 7.....theres one and the next ? is  solve 2x - 4 = 7  justify each step<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #7779 by </B><A HREF=/tutors/aboutme.mpl?userid=pwac><B>pwac(253)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=pwac><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=7779\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First find t<BR>\n" );
document.write( "2t+3=-9 Subtract 3 from both sides<BR>\n" );
document.write( "2t=-12  Divide both sides by 2<BR>\n" );
document.write( "t=-6\r<BR>\n" );
document.write( "\n" );
document.write( "Now put this value of t into -3t-7<BR>\n" );
document.write( "-3(-6)=18<BR>\n" );
document.write( "18-7=11\r<BR>\n" );
document.write( "\n" );
document.write( "2x-4=7 Add 4 to both sides:<BR>\n" );
document.write( "2x=11 Divide both sides by 2<BR>\n" );
document.write( "x=11/2=5.5\r<BR>\n" );
document.write( "\n" );
document.write( "Pete </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );