document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1155307>Question 1155307</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Use algebraic procedures to find the exact solution or solutions of the equation.\r<BR>\n" );
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document.write( "log(11x)-log3 = log(4x+1)\r<BR>\n" );
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document.write( "everything is to the base 9.\r<BR>\n" );
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document.write( "Thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #777888 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=777888\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> log(11x)-log3 = log(4x+1)<BR>\n" );
document.write( "everything is to the base 9.<BR>\n" );
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document.write( "log(11x/3) = log(4x+1)<BR>\n" );
document.write( "11x/3 = 4x+1<BR>\n" );
document.write( "11x = 12x+3<BR>\n" );
document.write( "-x = 3<BR>\n" );
document.write( "x = -3<BR>\n" );
document.write( "---> logs of negative numbers, not allowed.<BR>\n" );
document.write( "No solution. </SPAN>\n" );
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