document.write( "Question 1155290: A driver took a day-trip driving at two different speeds. He drove 50 miles at a slower speed and 140 miles at a speed 10 miles per hour faster. If the time spent during the faster speed was twice that spent at a slower speed, find the two speeds during the trip. \n" ); document.write( "

Algebra.Com's Answer #777863 by greenestamps(13200) $\"\"$ $\"About$

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\n" ); document.write( "time = distance / rate

\n" ); document.write( "x = lower speed
\n" ); document.write( "x+10 = higher speed

\n" ); document.write( "time to go 50 miles at lower speed: 50/x
\n" ); document.write( "time to go 140 miles at higher speed: 140/(x+10)

\n" ); document.write( "The time at the higher speed is twice the time at the lower speed:

\n" ); document.write( " $\"140%2F%28x%2B10%29+=+2%2A%2850%2Fx%29\"$

\n" ); document.write( " $\"140%2F%28x%2B10%29+=+100%2Fx\"$

\n" ); document.write( " $\"100x%2B1000+=+140x\"$

\n" ); document.write( " $\"1000+=+40x\"$

\n" ); document.write( " $\"x+=+25\"$

\n" ); document.write( "The two speeds are 25mph and 35mph.

\n" ); document.write( "CHECK:
\n" ); document.write( "50 miles at 25mph = 2 hours
\n" ); document.write( "140 miles at 35mph = 4 hours

\n" ); document.write( " \n" ); document.write( "

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