document.write( "Question 1155104: two-column proof
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document.write( "Given: AD is a diameter of ⊙ O;
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document.write( "Dc is tangent to ⊙ O at D.
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document.write( "Prove: ∆ABD ~ ∆ADC\r
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Algebra.Com's Answer #777829 by mananth(16949) You can put this solution on YOUR website! \r \n" ); document.write( "\n" ); document.write( "In triangle ABD & ADC \r \n" ); document.write( "\n" ); document.write( " ABD is congruent to angle ADC Both right angles \n" ); document.write( "(In ABD tangent perpendicular to radius \n" ); document.write( "ADC angle in a semi circle)\r \n" ); document.write( "\n" ); document.write( "angle A is common in both triangles\r \n" ); document.write( "\n" ); document.write( "Therefore ∆ABD ~ ∆ADC ( AA test of similarity) \n" ); document.write( " |