document.write( "Question 1155104: two-column proof
\n" ); document.write( "Given: AD is a diameter of ⊙ O;
\n" ); document.write( "Dc is tangent to ⊙ O at D.
\n" ); document.write( "Prove: ∆ABD ~ ∆ADC\r
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Algebra.Com's Answer #777829 by mananth(16949)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "In triangle ABD & ADC \r
\n" ); document.write( "\n" ); document.write( " ABD is congruent to angle ADC Both right angles
\n" ); document.write( "(In ABD tangent perpendicular to radius
\n" ); document.write( "ADC angle in a semi circle)\r
\n" ); document.write( "\n" ); document.write( "angle A is common in both triangles\r
\n" ); document.write( "\n" ); document.write( "Therefore ∆ABD ~ ∆ADC ( AA test of similarity)
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