document.write( "Question 15753: I've been trying to figure this problem out for more than a week and cant get it yet. Id really appreciate the help.\r
\n" ); document.write( "\n" ); document.write( "Find four consecutive integers such that the sum of the two largest subtracted from twice the sum of the two smallest is 15.
\n" ); document.write( " Let x= 1st number
\n" ); document.write( " x+1= 2nd number
\n" ); document.write( " x+2= 3rd number
\n" ); document.write( " x+3= 4th number
\n" ); document.write( " 2(x+x+1)-x+2+x+3=15
\n" ); document.write( " 2x+2x+2-x+2+x+3=15
\n" ); document.write( " 4x+2-2x+5=15
\n" ); document.write( " 2x+7=15
\n" ); document.write( " 2x=8
\n" ); document.write( " 4 (the numbers are 4,5,6,7 they dont solve the problem)\r
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Algebra.Com's Answer #7778 by pwac(253)\"\" \"About 
You can put this solution on YOUR website!
You were doing fine until 4x+2-2x+5=15
\n" ); document.write( "If you express it like this(4x+2)-(2x+5)=15 you may spot your error
\n" ); document.write( "you need to subtract(+5)from(+2).The equation will then be:
\n" ); document.write( "2x-3=15 so:
\n" ); document.write( "2x=18
\n" ); document.write( "x=9
\n" ); document.write( "Integers are then 9,10,11,12.\r
\n" ); document.write( "\n" ); document.write( "Pete
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