document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1155245>Question 1155245</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello Tutors...thank you for all your help on this site.Here's my question:2+log rad 1+x plus 3log rad 1-x =rad 1-x^2  this is what i did so far.2 +log rad 1+x plus 3log rad 1_x =log rad 1-x + log rad 1+x.<BR>\n" );
document.write( " ..this is as far as i got. i hope for some step by step on how to do this logarithm. thanks to all for the help. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #777797 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=777797\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "You're practically there...!<br><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%2Blog%28%28sqrt%281%2Bx%29%29%29%2B3log%28%28sqrt%281-x%29%29%29+=+log%28%28sqrt%281-x%5E2%29%29%29 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" ><br><BR>\n" );
document.write( "You saw the sqrt(1+x) and sqrt(1-x) on the left so you worked on the right:<br><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%2Blog%28%28sqrt%281%2Bx%29%29%29%2B3log%28%28sqrt%281-x%29%29%29+=+log%28%28sqrt%281-x%29%29%29%2Blog%28sqrt%281%2Bx%29%29%29 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" ><br><BR>\n" );
document.write( "Cancel the like terms on the two sides and work with what is left.  It will be an easy equation to solve if you have a basic understanding of logarithms.<br><BR>\n" );
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