document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1155243>Question 1155243</A>: <I><SPAN STYLE=\"word-break: break-all;\"> given the function f(x)=-3x^2+5x<BR>\n" );
document.write( "find F(-x) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #777794 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=777794\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> to find f(-x) given f(x) = -3x^2 + 5x, you replace x with -x.<BR>\n" );
document.write( "f(-x) would be equal to -3 * (-x)^2 + 5 * (-x) which becomes:<BR>\n" );
document.write( "f(-x) = -3x^2 - 5x<BR>\n" );
document.write( "the x^2 term windes up being the same because (-x)^2 = x^2<BR>\n" );
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