document.write( "Question 1155132: Find the area of the region in the first quadrant bounded by the line y=3x, the line x=5, the curve y= $\"3%2Fx%5E2\"$ , and the x-axis. \n" ); document.write( "

Algebra.Com's Answer #777709 by MathLover1(20850) $\"\"$ $\"About$

You can put this solution on YOUR website!

\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "the area $\"3x\"$ from $\"0\"$ to $\"1\"$ is a right triangle , length of its legs are $\"1\"$ and $\"3\"$ \r
\n" ); document.write( "\n" ); document.write( "=> the area is: $\"3%2A1%2F2=3%2F2=1.5+\"$ \r
\n" ); document.write( "\n" ); document.write( "then,take integral of $\"3%2Fx%5E2\"$ from $\"1\"$ to $\"5\"$ \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " $\"int%281-%3E5%29\"$ $\"+%283%2Fx%5E2%29%2Adx%29\"$ ...take the constant out\r
\n" ); document.write( "\n" ); document.write( " $\"3%2Aint%281-%3E5%29\"$ $\"+%281%2Fx%5E2%29%2Adx%29\"$ ....... $\"1%2Fx%5E2=x%5E-2\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"3%2Aint%281-%3E5%29\"$ $\"+%28x%5E-2%29%2Adx%29\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"3%2A%284%2F5%29\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"12%2F5%29\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"2.4%29\"$ \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "total area: $\"1.5%2B2.4=3.9+\"$
\n" ); document.write( " \n" ); document.write( "

\n" );