document.write( "Question 106890: 1/ Square root of 5 minus the square root of 2 \n" ); document.write( "

Algebra.Com's Answer #77770 by MathLover1(20850) $\"\"$ $\"About$

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1/ Square root of 5 minus the square root of 2\r
\n" ); document.write( "\n" ); document.write( "if we have:\r
\n" ); document.write( "\n" ); document.write( " $\"1%2Fsqrt%285%29+\"$ – $\"sqrt%282%29%29\"$ multiply both terms by $\"sqrt%285%29\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"1+\"$ – $\"sqrt%282%29sqrt%285%29\"$ \r
\n" ); document.write( "\n" ); document.write( "Since $\"a+=+2\"$ and $\"b+=+5\"$ both are positive real numbers, we can use the following are some property of square root function. \r
\n" ); document.write( "\n" ); document.write( " $\"sqrt%28a%29sqrt%28b%29+=+sqrt%28ab%29\"$ \r
\n" ); document.write( "\n" ); document.write( "or\r
\n" ); document.write( "\n" ); document.write( " $\"sqrt%282%29sqrt%285+%29+=+sqrt%2810%29\"$ \r
\n" ); document.write( "\n" ); document.write( "Then we have\r
\n" ); document.write( "\n" ); document.write( " $\"1+\"$ – $\"sqrt%282%29sqrt%285%29\"$ = $\"1+\"$ – $\"sqrt%2810%29\"$ = $\"1+-+1.78\"$ = $\"-.78\"$ \r
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\n" ); document.write( "\n" ); document.write( "2.
\n" ); document.write( "in case you mean:\r
\n" ); document.write( "\n" ); document.write( " $\"1%2F%28sqrt%285%29+-+sqrt%282%29%29+=+1%2F%282.24-+1.19%29+=+1%2F1.05+=+0.95\"$
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