document.write( "Question 1155133: Use an ordinary proof (not conditional or indirect proof):
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document.write( "1. K∨(S • N)
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document.write( "2. ∼(K •∼Q)
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document.write( "3. ∼(N •∼Q) / Q\r
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Algebra.Com's Answer #777698 by Edwin McCravy(20055)![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( " 1. K∨(S • N) \r\n" ); document.write( " 2. ∼(K •∼Q) \r\n" ); document.write( " 3. ∼(N •∼Q) / Q\r\n" ); document.write( "\r\n" ); document.write( " 4. ~K∨~~Q 2, DeMorgan's law\r\n" ); document.write( " 5. ~K∨Q 4, Double negation\r\n" ); document.write( " 6. ~N∨~~Q 3, DeMorgan's law\r\n" ); document.write( " 7. ~N∨Q 6, Double negation\r\n" ); document.write( " 8. Q∨~K 5, Commutation\r\n" ); document.write( " 9. Q∨~N 7, Commutation\r\n" ); document.write( "10. (Q∨~K)•(Q∨~N) 8,9, Conjunction\r\n" ); document.write( "11. Q∨(~K•~N) 10, Distribution\r\n" ); document.write( "12. Q∨~(K∨N) 11, DeMorgan's law\r\n" ); document.write( "13. (K∨S)•(K∨N) 1, Distribution\r\n" ); document.write( "14. (K∨N)•(K∨S) 13, Commutation\r\n" ); document.write( "15. K∨N 14, Simplification\r\n" ); document.write( "16. ~~(K∨N) 15, Double negation\r\n" ); document.write( "17. ~(K∨N)∨Q 12, Commutation\r\n" ); document.write( "18. Q 17,16, Disjunctive syllogism\r\n" ); document.write( "\r\n" ); document.write( "Edwin\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |