document.write( "Question 1155099: The sides of triangle XYZ are XY = XZ = 25 and YZ = 40. A semicircle is inscribed in triangle XYZ so that its diameter lies on YZ, and is tangent to the other two sides. Find the area of the semicircle. \n" ); document.write( "
Algebra.Com's Answer #777693 by ikleyn(52786)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( " \r\n" ); document.write( "\r\n" ); document.write( "You are given the isosceles triangle XYZ.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Draw the perpendicular (the height, the altitude) from the vertex X to the base YZ.\r\n" ); document.write( "\r\n" ); document.write( "Let A be the foot of this altitude.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "According to the WELL KNOWN property of isosceles triangles, the altitude XA is the median at the same time.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Thus the original triangle XYZ is divided in two congruent right angled triangles XYA and XZA.\r\n" ); document.write( "\r\n" ); document.write( "Their legs YA and ZA are 40/2 = 20 units long (each).\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "So, each of these two right angled triangles is (3,4,5) triangles with the hypotenuse of 25 inits long and \r\n" ); document.write( "\r\n" ); document.write( "with the legs of 20 units long (YA and ZA) and 15 units long (the altitude XA).\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "The area of each of the two right angled triangles is\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |