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document.write( "Its graph is this:\r\n" );
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document.write( "In order for it to be a probability density function, it must be such that when\r\n" );
document.write( "we shade the area between it and the x-axis, that area must be exactly 1.\r\n" );
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document.write( "It's a probability density function because the area between it and the x-axis\r\n" );
document.write( "is a triangle whose base is 4 and whose height is 1/2 or 0.5 since when we\r\n" );
document.write( "substitute x=5 in (𝑥−1)/8 we get 4/8 or 1/2 or 0.5 and the area of a triangle is\r\n" );
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document.write( "Since the entire area between the graph and the x-axis is 1, it is indeed a\r\n" );
document.write( "probability density function. So the problem was telling the truth when it said\r\n" );
document.write( "this is a probability density function.\r\n" );
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document.write( "The probability that 𝑋 is between two values is the area between the graph and\r\n" );
document.write( "the x-axis between those two values.\r\n" );
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A. Find the probability that 𝑋 lies between 2 and 4.\r\n" );
document.write( "This asks for the area between 2 and 4, which is this shaded area:\r\n" );
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document.write( "This is a trapezoid (or 'trapezium' if you live in the UK), and if you turn your\r\n" );
document.write( "head 90° it has two bases b1=0.125 and b2=0.25, and \r\n" );
document.write( "height = 2. The formula for the area is\r\n" );
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document.write( "So that's the answer.\r\n" );
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B. Find the probability that 𝑋 is less than 3.\r\n" );
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document.write( "the shaded area between between the graph the x-axis is a triangle whose base is\r\n" );
document.write( "2 and whose height is 1/4 or 0.25 since when we substitute x=2 in (𝑥−1)/8 we get\r\n" );
document.write( "1/8 or 0.125 and the area of a triangle is \r\n" );
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document.write( "That's the answer.\r\n" );
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document.write( "Edwin
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