document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1155049>Question 1155049</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The exterior angle of a polygon is one third the interior angle .calculate the number of sides of the polygon  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #777594 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=777594\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let ext angle be x<BR>\n" );
document.write( "interior angle will be 3x\r<BR>\n" );
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document.write( "sum = 180 deg<BR>\n" );
document.write( "4x=180<BR>\n" );
document.write( "x=45 degree\r<BR>\n" );
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document.write( "Formula for interior angle with n  sides<BR>\n" );
document.write( "Thetha = (n-2)*180/n<BR>\n" );
document.write( "135 = (n-2)*180/n\r<BR>\n" );
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document.write( "135 n = 180n -360 \r<BR>\n" );
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document.write( "45n =360<BR>\n" );
document.write( "n =8<BR>\n" );
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