document.write( "Question 106861: I did what I was supposed to do on this equation, but my answers did not check out. 2/x+5/2x=1. How do you solve this problem? Thank you. \n" ); document.write( "
Algebra.Com's Answer #77755 by checkley75(3666)\"\" \"About 
You can put this solution on YOUR website!
2/X+5/(2X)=1 NOW COMBINE THE LEFT SIDE FRACTIONS
\n" ); document.write( "(2*2X+5*X)/2X*X=1
\n" ); document.write( "(4X+5X)/2X^2=1 NOW CROSS MULTIPLY
\n" ); document.write( "2X^2=4X+5X
\n" ); document.write( "2X^2-9X=0
\n" ); document.write( "X(2X-9)=0
\n" ); document.write( "2X=9
\n" ); document.write( "X=9/2
\n" ); document.write( "X=4.5 ANSWER.
\n" ); document.write( "PROOF
\n" ); document.write( "2/4.5+5/2*4.5=1
\n" ); document.write( "4/9+5/9=1
\n" ); document.write( "9/9=1
\n" ); document.write( "1=1
\n" ); document.write( "OR IF YOU MENT: 2/X+(5/2)X=1 THEN:
\n" ); document.write( "2/X+2.5X=1
\n" ); document.write( "(2+2.5X*X)/X=1
\n" ); document.write( "(2+2.5X^2)/X=1 NOW CROSS MULTIPLY
\n" ); document.write( "2+2.5X^2=X
\n" ); document.write( "2.5X^2-X+2=0
\n" ); document.write( "USING THE QUADRATIC EQUATION \"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( "WE GET:
\n" ); document.write( "X=(1+-SQRT[-1^2-4*2.5*2])/2*2.5
\n" ); document.write( "X=(1+-SQRT[1-20])/5
\n" ); document.write( "X=(1+-SQRT-19)/5
\n" ); document.write( "X=(1+-4.36i)/5
\n" ); document.write( "X=(1+4.36i)/5
\n" ); document.write( "X=1/5+.872i
\n" ); document.write( "X=.2+.872i ANSWER.
\n" ); document.write( "X=(1-4.36i)/5
\n" ); document.write( "X=.2-.872i ANSWER.\r
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