document.write( "Question 1154996: A manufacturer of window frames knows from long experience that 20% of the production will have some type of minor defect that will require an adjustment. What is the probability that in a sample of 16 window frames:\r
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\n" ); document.write( "\n" ); document.write( "a. None will need adjustment? (Round the final answer to 3 decimal places.)\r
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\n" ); document.write( "\n" ); document.write( "Probability
\n" ); document.write( "0.028\r
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\n" ); document.write( "\n" ); document.write( "b. At least one will need adjustment? (Round the final answer to 3 decimal places.)\r
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\n" ); document.write( "\n" ); document.write( "Probability
\n" ); document.write( "0.972\r
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\n" ); document.write( "\n" ); document.write( "c. More than two will need adjustment? (Round the final answer to 3 decimal places.)\r
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Algebra.Com's Answer #777547 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!

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\n" ); document.write( "n = 16, p = .2 defective
\n" ); document.write( "c. More than two will need adjustment? (Round the final answer to 3 decimal places.)
\n" ); document.write( "P(More than two will need adjustment) = 1 - P(2 or less)\r
\n" ); document.write( "\n" ); document.write( "P(More than two will need adjustment)= 1- binomcdf(16,.2, 2)
\n" ); document.write( "Wish You the Best in your Studies. \n" ); document.write( "
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