document.write( "Question 1154982: Allen is 25 years older than Beth. In 10 years, Allen will be twice as old as Beth. How old are Allen and Beth right now?
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Algebra.Com's Answer #777520 by greenestamps(13198)\"\" \"About 
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\n" ); document.write( "Algebraically....

\n" ); document.write( "x = Beth's age
\n" ); document.write( "x+25 = Allen's age

\n" ); document.write( "x+10 = Beth's age in 10 years
\n" ); document.write( "x+35 = Allen's age in 10 years

\n" ); document.write( "x+35 = 2(x+10)

\n" ); document.write( "Solve using basic algebra.

\n" ); document.write( "By logical reasoning (good mental exercise, if an algebraic solution is not required)....

\n" ); document.write( "The difference in their ages will always be 25 years.
\n" ); document.write( "So when Allen is twice as old as Beth, their ages will be 25 and 50.
\n" ); document.write( "Since that will be 10 years from now, their current ages are 15 and 40.

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