document.write( "Question 1154970: the age of the older of 2 brothers is double of that of the younger . however 6 years ago it was 4 times that of the younger. what are their ages in years? \n" ); document.write( "
Algebra.Com's Answer #777506 by mananth(16946)\"\" \"About 
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\n" ); document.write( "the age of the older of 2 brothers is double of that of the younger . however 6 years ago it was 4 times that of the younger. \r
\n" ); document.write( "\n" ); document.write( "let younger brother's age be x\r
\n" ); document.write( "\n" ); document.write( "Elder brother's age is 2x\r
\n" ); document.write( "\n" ); document.write( "6 years ago\r
\n" ); document.write( "\n" ); document.write( "younger's age = x-6\r
\n" ); document.write( "\n" ); document.write( "Elder's age was 2x-6\r
\n" ); document.write( "\n" ); document.write( "Relation
\n" ); document.write( "2x-6 = 4(x-6)\r
\n" ); document.write( "\n" ); document.write( "2x-6 = 4x-24\r
\n" ); document.write( "\n" ); document.write( "2x=18
\n" ); document.write( "x=9
\n" ); document.write( "2x =18\r
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