document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1154961>Question 1154961</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 2 meters more than 4 times the width. If the area is 156 square meters, find the width and the length.\r<BR>\n" );
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document.write( "Width:______meters <BR>\n" );
document.write( "Length:_____meters </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #777477 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=777477\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let width be x\r<BR>\n" );
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document.write( "length =4x+2\r<BR>\n" );
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document.write( "Area = x(4x+2)=156 \r<BR>\n" );
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document.write( "4x^2+2x-156=0\r<BR>\n" );
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document.write( "2x^2+x-78=0\r<BR>\n" );
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document.write( "(2x+13)(x-6)=0\r<BR>\n" );
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document.write( "Ignore negative<BR>\n" );
document.write( "x=6<BR>\n" );
document.write( "width = 6<BR>\n" );
document.write( "plug x to find length </SPAN>\n" );
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